(5b^3+3b^2+28)/(b+2)

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Solution for (5b^3+3b^2+28)/(b+2) equation: 


D( b )

b+2 = 0

b+2 = 0

b+2 = 0

b+2 = 0 // - 2

b = -2

b in (-oo:-2) U (-2:+oo)

(5*b^3+3*b^2+28)/(b+2) = 0

5*b^3+3*b^2+28 = 0

5*b^3+3*b^2+28 = 0

{ 1, -1, 2, -2, 4, -4, 7, -7, 14, -14, 28, -28 }

1

b = 1

5*b^3+3*b^2+28 = 36

1

-1

b = -1

5*b^3+3*b^2+28 = 26

-1

2

b = 2

5*b^3+3*b^2+28 = 80

2

-2

b = -2

5*b^3+3*b^2+28 = 0

-2

b+2

5*b^2-7*b+14

5*b^3+3*b^2+28

b+2

-5*b^3-10*b^2

28-7*b^2

7*b^2+14*b

14*b+28

-14*b-28

0

5*b^2-7*b+14 = 0

DELTA = (-7)^2-(4*5*14)

DELTA = -231

DELTA < 0

b in { -2} 

b+2 = 0

1 = 0

b belongs to the empty set

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